tentukan keliling dari bangun datar berikut!
- Sisi miring
[tex] = \sqrt{ {12}^{2} + {9}^{2} } [/tex]
[tex] = \sqrt{144 + 81} [/tex]
[tex] = \sqrt{225} [/tex]
= 15
- keliling
= 2(15 + 21 + 9)
= 2(45)
= 90 satuan
AF࿐
penyelesaian :
mencari sisi miring :
= √B² + A²
= √12² + 9²
= √144 + 81
= √225
= 15 cm
keliling :
= 2 × ( a + c )
= 2 × ( 30 + 15 )
= 2 × 45
= 90 cm
[answer.2.content]
